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![]() Reebok Sickick 11K Pro Stock Hockey Stick - RH Letestu US $159.99
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11k Stick
Three Techniques The Pros Use To Get RSS Subscribers To Remain Subscribers
Your RSS subscribers are a vital source of traffic, which is why you should do everything to ensure they stay happy and not leave. If you want to keep your subscribers right where they're at, you can't go wrong with the three tips below.
One of the first tips that you need to remember in order to retain your RSS subscribers is to provide them with original content. You never want to take content from other sites because that will tell people that you're not really serious. You goal is to get your subscribers to remain with your feed by giving them content they can't find in other places. It's just like selling products, as people will feel cheated if you sell them a fake product. It's really not that hard to be original; whenever you create new content make sure you add your own personality to it and give it a more authentic look. There are many bloggers that have gained massive popularity only because they kept giving their readers content that is valuable and rare.
When you think of your subscriber, they'll always think of you. Keep in mind that it's harder to keep people as your RSS subscribers than it is to get them in the first place.
When creating your content, make sure it's easy for your readers to take in. You need to make your content scannable and at the same time make the navigation easy. If you're writing a long post, break it down into paragraphs, but not too many.
Your posts need to be formatted with a certain balance in mind so that readers have no problems finding the information they want. People's time is short when it comes to reading things online, so always remember that when creating your posts. Besides that, your content will be liked and spread around if you make it organized and appealing to your subscribers. And that is one more way to keep them as subscribers.
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Frequently Asked Questions...
Basic Mathematics help. Discriminant. Show that (k-1)(11k 25)≤0?
Basically i have a homework question which i cant figure out :S
Part a) simplify (k+5)² - 12k(k+2)
- My answer: -11k²-14k-25
Part b) The Quadratic equation 3(k+2)p² +(k+5)p+k=0 has real roots.
i) Show that (k-1)(11k 25) ≤0
I'm stuck at Part B
so far i have expanded it so its 11k² + 14k - 25 ≤0
know i have no idea what to do next?
Part ii) hence find possible values of K - think might be able to this one
Thankyou!
sorry its (k-1)(11k+25)≤0
Answer:
(In part a it's +25 not -25 btw)
If it has real roots then the discriminant b² - 4ac is greater than or equal to 0
(k+5)² - 4*3(k+2)*k>=0
k² +10k+25-12k² -24k >=0
-11k²-14k+25>=0
11k²+14k-25≤0
(k-1)(11k+25)≤0
(above you are using the simplification from part a))
So as you probably know -25/11<=k<=1









































